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\frac{134}{60} \div 5 = \frac{134}{60} \cdot \frac{1}{5} = \frac{134}{300}

paw.KaTeX{
	TeX:  `\frac{134}{60} \div 5 = \frac{134}{60} \cdot \frac{1}{5} = \frac{134}{300}`,
	Size: 24,
}

\displaystyle \frac{1}{\Bigl(\sqrt{\phi \sqrt{5}}-\phi\Bigr) e^{\frac25 \pi}} = 1+\frac{e^{-2\pi}} {1+\frac{e^{-4\pi}} {1+\frac{e^{-6\pi}} {1+\frac{e^{-8\pi}} {1+\cdots} } } }

paw.KaTeX{
	TeX:  `\displaystyle \left( \sum_{k = 1}^n a_k b_k \right)^2 \leq \left( \sum_{k = 1}^n a_k^2 \right) \left( \sum_{k = 1}^n b_k^2 \right)`,
}

\displaystyle \left( \sum_{k = 1}^n a_k b_k \right)^2 \leq \left( \sum_{k = 1}^n a_k^2 \right) \left( \sum_{k = 1}^n b_k^2 \right)

\begin{align*} 7\left(\frac{11}{14}\right)^3-9\left(\frac{11}{14}\right)-9\left(\frac{1}{2}\right)^2+52+3\left(\frac{1}{2}\right)&=7\cdot\frac{1331}{2744}-\frac{99}{14}-\frac{9}{4}+52+\frac{3}{2}\\ &=\frac{9317}{2744}-\frac{99}{14}-\frac{9}{4}+\frac{105}{2}\\ &=\frac{9317}{2744}+\frac{735}{28}-\frac{63}{4}\\ &=\frac{9317}{2744}+\frac{6615}{616}-\frac{819}{616}\\ &=\frac{9317+6615-819}{2744}=\boxed{\frac{1513}{308}}. \end{align*}

\displaystyle {1 + \frac{q^2}{(1-q)}+\frac{q^6}{(1-q)(1-q^2)}+\cdots }= \prod_{j = 0}^{\infty}\frac{1}{(1-q^{5j+2})(1-q^{5j+3})}, \quad\quad \text{for }\lvert q\rvert<1.